-16x^2+860=0

Solution for -16x^2+860=0 equation:

-16x^2+860=0

a = -16; b = 0; c = +860;
Δ = b2-4ac
Δ = 02-4·(-16)·860
Δ = 55040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{55040}=\sqrt{256*215}=\sqrt{256}*\sqrt{215}=16\sqrt{215}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{215}}{2*-16}=\frac{0-16\sqrt{215}}{-32}
=-\frac{16\sqrt{215}}{-32}
=-\frac{\sqrt{215}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{215}}{2*-16}=\frac{0+16\sqrt{215}}{-32}
=\frac{16\sqrt{215}}{-32}
=\frac{\sqrt{215}}{-2}
$